Calculate the oxidation number of the underlined elements:
Let the oxidation number of each element to be found be x in each cases.
Here,ON of K, H = 1;ON of O = -2
a) KMnO4
It is a molecule hence, the ON of the molecule is zero.
1 + x + 4(-2) = 0
1 + x - 8 = 0
x - 7 = 0
x = 7
b) K2Cr2O7
It is a molecule hence, the ON of the molecule is zero.
2(1) + 2(x) + 7(-2) = 0
1 + x - 7 = 0
x - 6 = 0
x = 6
c) H2SO4
It is a molecule hence, the ON of the molecule is zero.
2(1) + x + 4(-2) = 0
2 + x - 8 = 0
x - 6 = 0
x = 6
d) CO32-
It is a radical that has -2 charge so, the ON of the...