How many mL of a 0.1 M HCl are required to react completely with a 1gm mixture of Na2CO3 and NaHCO3 containing the equimolar amount of the two.
The number of moles of a solute dissolved in 1 L (1000 ml) of the solutionis known as the molarity of the solution.
Molarity * mol. wt = %(w/v) * 10
Molarity = 93*10/98 ==> 9.489
|1. It is the number of gram equivalents of solute dissolved per litre solution.||1. It is the number of gram molecules of solute dissolved per litre its solution.|
|2. In general, Normality(N) = (g/L)/eq. wt||2. Molarity(M) = (w*1000)/(v* mol. wt)|
Deci- Normal solution ---->The solution containing 1/10 mole of solute in 1 liter of solution is called normal solution.
Deci-molar solution(M10):The solution containing 110 th mole of solute in 1 liter of solution is known as decinormal solution.