1). Molecular formula of C6H12O6. Calculate a). molecular mass of the compound b).mass ratio and % composition of elements present in the compound2). Empirical formula of glucose is CH2O. Find...
Questions no. 1(a)
Solutions:
Given, Molecular formula of glucose is C6H12O6.
Here, Atomic mass of one C inC6H12O6= 12 amu
Atomic mass of one H inC6H12O6= 1 amu
Atomic mass of one O inC6H12O6= 16 amu
Now, molecular mass of the compound = (6*12)+(12*1)+(6*16)=180 units
Question no.1(b).
Solutions:
Given, Molecular formula of glucose isC6H12O6.
Here, Mass of C inC6H12O6= 6*12 =72
Mass of H inC6H12O6=12*2 = 24
Mass of O inC6H12O6= 6*16 =96
Now, mass ratio of C:H:O = 72 : 24 : 96 = 3 :1 :...