21 Chemistry -- Foundation and Fundamentals of Chemistry

How many electrons and neutrons are present in the symbol 2713Al3+?

How many electrons and neutrons are present in the symbol 2713Al3+?

Atomic no. (Z) = 13 and atomic mass (A) = 27
No. of neutrons = A-Z = 27 - 13 = 14
No. of electrons = 13 - 3 = 10

Al atom loses 3e- to form Al+3.

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