Question no i)
Solution:
Given, Naturally occuring neon is 90.9% neon-20, 0.3% neon-21, 8.8% neon-22.
Now, the relative atomic mass of naturally occuring neon = ( mass number of isotope neon-20) x ( abundance%) + ( mass number of isotope neon-21) x (abundance%) + ( mass number of isotope neon-22) x (abundance%)/100%
= [(20x90.9%) + (21x0.3%) + (22x8.8%)] /100%
= (1818% + 6.3% + 193.6% ) /100%
=( 2017.9%) /100%
= 20.179
Question no ii)
Solution:
Given, A natural mixture of hydrogen contains 1H1 and 1H2 . And the average atomic mass of hydrogen is 1.008 amu.
In this question, we are given two isotopes of Hydrogen.
Mass of isotope 1H1 = 1amu.
Mass of isotope 1H2 = 2amu.
Fractional abundance of isotope 1H1 = x
Fractional abundance of isotope 1H2= (1- x).
To calculate average atomic mass of an element, we use the formula:
Average Atomic mass of Hydrogen = (Fractional abundance of isotope 1H1) *(mass of isotope 1H1) + (Fractional abundance of isotope 1H2) * (mass number of isotope 1H2)
Putting the given information, we get,
Or, 1.008 amu = (1amu *x) + {2amu*(1-x)}
Or, 1.008 = x+ 2 - 2x
Or, x = 0.992
Then, fractional abundance percentage of isotope 1H1 (x) = 0.992*100% = 99.2%
Also, the fractional abundance percentage of isotope 1H2 (1-x) = (100 - 99.2)% = 0.8%