A divalent metal oxide contains 60% of metal. What is atomic weight of metal?
wt of metal= 60 g
wt of oxygen= (100-60) g= 40 g
Eq. wt. of metal = wt. of metal/ wt of oxygen* 8
= 12
As metal is divalent, At. wt= Eq. wt* valency= 12*2 = 24
How many grams of sulphur and oxygen are needed to produce 6.023 x 1024 molecules of SO2 according to the reaction?
S + O2 → SO2
The balanced chemical equation is given as:
S + O2 → SO2
According to the reaction
6.022 x 1023 molecules of SO2 are produced from 32g sulphur.
6.022 x 1024 molecules of SO2 are produced from = 320g sulphur
Similarly,
6.022 x 1023 molecules of SO2 are produced from 32g of oxygen
6.022 x 1024 molecules of SO2 can be produced from = 320g oxygen