A divalent metal oxide contains 60% of metal. What is atomic weight of metal?
wt of metal= 60 g
wt of oxygen= (100-60) g= 40 g
Eq. wt. of metal = wt. of metal/ wt of oxygen* 8
= 12
As metal is divalent, At. wt= Eq. wt* valency= 12*2 = 24
0.36 gm of a metal when burnt in oxygen yields 0.60 gm oxide. The
carbonate of that metal contains 28.57% of the metal. Assuming the validity
of the law of definite proportions, determine the weight of the oxide formed by heating 1 gm of that carbonate.