A divalent metal oxide contains 60% of metal. What is atomic weight of metal?
wt of metal= 60 g
wt of oxygen= (100-60) g= 40 g
Eq. wt. of metal = wt. of metal/ wt of oxygen* 8
= 12
As metal is divalent, At. wt= Eq. wt* valency= 12*2 = 24
How many number of oxygen molecules are required to produce 220mg of CO2 according to the reaction?
C + O2 → CO2
The balanced chemical equation is given as
C + O2 → CO2
Given mass of CO2 = 220mg = 0.22g
44g of CO2 is produced from 6.022 x 1023 oxygen molecules.
0.22g of CO2 can be produced from 3.011 x 1021 oxygen molecules.