21 Chemistry -- Stoichiometry

How many number of moles of CO will be left when 2 x 1021 molecules are removed from 0.28g of CO?

How many number of moles of CO will be left when 2 x 1021 molecules are removed from 0.28g of CO?

Given,

The given weight of CO = 0.28 g
The molecular weight of CO = 28g

No. of moles of CO = 0.01 mole

We know that,

1 mole of CO contains 6.022 x 1023 molecules
0.01 mole of CO contains 0.01 x 6.022 x 1023 molecules = 6.022 x 1021 molecules

The number of molecules left is (6.022 x 1021 - 2 x 1021) = 4.022 x 1021 molecules

We know that,

6.022 x 1023 molecules of CO = 1 mole of CO

4.012 x 1021 molecules of CO = 6.68 x 10-3

Hence, no. of mole of CO left is 6.68 x 10-3

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