A divalent metal oxide contains 60% of metal. What is atomic weight of metal?
wt of metal= 60 g
wt of oxygen= (100-60) g= 40 g
Eq. wt. of metal = wt. of metal/ wt of oxygen* 8
= 12
As metal is divalent, At. wt= Eq. wt* valency= 12*2 = 24
Nitrogen reacts with oxygen to give N2O3 and N2O5 respectively. Which law of stoichiometry do this data illustrate? State the law.
Nitrogen combines with oxygen to form various oxide.
Compound | Combining | element | Ratio of | masses | with fixed | mass of N |
N2O3 | N | O | 28 | 48 | 14 | 24 |
N2O5 | N | O | 28 | 80 | 14 | 40 |
The ratio of different weight of oxygen 24, 40 combining with fixed weight of nitrogen 14 is 24:40 i.e. 3:5 which is simple whole number ratio. The given data illustrate the law of multiple proportions.
Statement:
"When two elements combine to form more than one compound, then the different weight of one element combining with a fixed weight of the other element are in simple numerical ratio with each other."