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Mousham khatiwada • about 1 year ago

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Rabin Kalikote

Happy Mother's Day, sir.

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Ashok Shah • 8 months ago

When Years of Academic Success Became a Tale of Failure!!

Aahan, a student, has always been deeply ingrained withacademic successin his life. From a young age, he was taught that hard work and dedication were the keys to achieving the goals. As a result, he dedicated countless hours to studying, completing assignments, and striving for top grades.The thrill of academic achievement was intoxicating. Each high grade was a validation of...

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Nikas Ghimire • almost 2 years ago

There are different ways to visualize infinity to ponder upon. This is some random thing about infinity in my head which I'll be mentioning.

Imagine any number, Keep on adding a certain value to it, Since we are talking big here, there is no limit to how much you add.

Keep on adding, Imagine that the progress of increment is like a progress bar. So, Is the progress bar really progressing? Since it doesnt really have an end and no...

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Rabin Kalikote

Where could be the end? Any thoughts?

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Nikas Ghimire

The end is when node_modules finishes installing.

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Saroj Shrestha • asked a question

How To Be Billionaire?

If one could be a billionaire by following a how-to guide step by step, you'd have already come across it by now.

Well, the how-to "BE" part is simple; own anything that's worth a billion- an idea, an asset, a skill, anything. It is the how-to reach that milestone that is mystic. Carve your own path to it.

Once you find the secret (IF there is one), share it on Mattrab :P

Or maybe don't ;) let others find their own path.

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Arya Jha • asked a question

Using bisection method, find the root of the equation f(x)=x² -6logx-3=0(2<=x<=3)'correct to 4 decimal places with an accuracy of 10^-2 .

Here, f(x)=x² -6 logx-3=0

f(2)=4-6 log2-3=-0.806

f(3)=9-6 log3-3=3.1373

f(2).f(3)=-0.806*3.1373=-2.529422 which is negative.

Hence, the root lies between 2 and 3

c₀ =(2+3)/2=2.5

f(2.5)=6.25-6 log 2.5-3=0.8623

Now

n	a(-ve)	b(+ve)	c_n	f(c_n)
0	2	3	2.5	0.8623
1	2	2.5	2.25	-0.050595
2	2.25	2.5	2.375	0.38664
3	2.25	2.375	2.3125	0.1631658
4	2.25	2.3125	2.28125	0.05506
5	2.25	2.28125	2.265625	0.001925

From the table,

f(2.265625)=0.001928<10^-2

Therefore, the...

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Ashok Shah • 4 months ago

Hey everyone, Today, I want to take a moment to revisit something special that happened recently. I was invited to my college where I completed my 11th and 12th to share my experiences from my +2...