Program to input any number and display number of odd numbers in it;
#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#include<string.h>
int main() {
int i, number, num1, num2=0, num3, num4 =0, rem, rem1, rem2, rev = 0;
printf("Enter your number ==> ");
scanf("%d", &number);
num1 = number;
while(num1 != 0) {
rem = num1%10;
rem1 = rem%2;
if (rem1 != 0) {
num2 = num2*10 + rem;
}
num1 /= 10;
}
num3 = num2;
while (num2 != 0) {
...
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Log2aa=x then, a=(2a)x ......(1)
Log3a2a=y then,2a=(3a)y ......(2)
Log4a 3a=z then, 3a=(4a)z ......(3)
So,
a=(2a)x [from (1)]
Or, a=(3a)xy [from(2)]
Or, a=(4a)xyz [from(3)]
Multiplying both sides by 4a,
4a.a=4a.(4a)xyz
Or,(2a)² =(4a)xyz + 1
Or,(3a)2y =(4a)xyz+1
Or,(4a)2yz =(4a)xyz+1
Or, 2yz = xyz+1 .proved.
