Nepal's Largest Social Learning Platform

Prashiddha Bista

Ashok Shah • over 2 years ago

Hey everyone, Today, I want to take a moment to revisit something special that happened recently. I was invited to my college where I completed my 11th and 12th to share my experiences from my +2...

5 Claps

0 Comments

Comment Read

Nikas Ghimire • almost 4 years ago

NASA has recently released the sharpest and deepest image of the universe. Making us realize again, How tiny we are.

8 Claps

1 Comments

Comment Read

gaurab giri

routine of nikas banda

Reply almost 4y

Nikas Ghimire • almost 4 years ago

There are different ways to visualize infinity to ponder upon. This is some random thing about infinity in my head which I'll be mentioning.

Imagine any number, Keep on adding a certain value to it, Since we are talking big here, there is no limit to how much you add.

Keep on adding, Imagine that the progress of increment is like a progress bar. So, Is the progress bar really progressing? Since it doesnt really have an end and no...

5 Claps

1 Comments

Comment Read

Rabin Kalikote

Where could be the end? Any thoughts?

Reply almost 4y

Nikas Ghimire

The end is when node_modules finishes installing.

almost 4y

Sushil Bhandari • asked a question

What is the roadmap from learner to creator or even admin?
What are the special facilities that the creator and admin get besides creating notes?
Is the traffic on mattrab increasing or is it...

Recently we're working to degrade accounts with 0 contributions from creator to learner. If you're a learner and very keen to be a creator, you must keep posting interesting questions and contact to admins from the Facebook Group of Mattrab Community. For being an admin, you must be in grade 12, either completed or recently enrolled, your notes, and all your records and contributions will be verified for that

7 Thanks

3 Answers

Answer Thread

Mattrab Community - SXC • asked a question

Log_2aa=x then, a=(2a)^x ......(1)

Log_3a2a=y then,2a=(3a)^y ......(2)

Log_4a 3a=z then, 3a=(4a)^z ......(3)

So,

a=(2a)^x [from (1)]

Or, a=(3a)^xy [from(2)]

Or, a=(4a)^xyz [from(3)]

Multiplying both sides by 4a,

4a.a=4a.(4a)^xyz

Or,(2a)² =(4a)^{xyz + 1}

Or,(3a)^2y =(4a)^xyz+1

Or,(4a)^2yz =(4a)^xyz+1

Or, 2yz = xyz+1 .proved.

9 Thanks

2 Answers

Answer Thread

Ashutosh Thapa • over 3 years ago

Guys I've exams from tomorrow

"PHYSICS "

Wish me luck!!!!

6 Claps

0 Comments

Comment Read

Kaushal Ghimire • over 3 years ago

The Moon

Silent and still, the moon shines bright
In the dark, clear sky
Peaceful and calm, the night
A soothing balm to the weary eye

The moon, a glowing orb of light
Illuminates the path ahead
As the night wind whispers through the trees
And the stars twinkle overhead

So let us lay down and rest
And let the moon and night provide
The peacefulness and solitude
That we all need to feel alive

9 Claps

0 Comments

Comment Read

EU 5 Series

Swarup Khatiwada

Ishan

Rabin Kalikote

Prashiddha Bista

Mattrab Community

EU 5 Series

Swarup Khatiwada

Ishan

Rabin Kalikote

Prashiddha Bista

Mattrab Community

Ask Mattrab is changing soon