#include<stdio.h>

#include<conio.h>

#include<string.h>

int main() {

int i, number, num1, num2=0;

char str1[50];

num1 = number;

for(i=2; i<=20; i+=2) {

printf("%d", i);

printf(", ");

}

return 0;

}

4.कमपयुटर हारडवेयर तिन परकारमा विभाजित छ। तिनीहरू हुन :

Here, the given equation of parabola is y²= 8x.

The equation of tangent to the parabola y²=8x is,

y= mx + 2/m

This tangent passes through the point (-2, 3)

So, 3 = -2m + 2/m

or, 3m + 2m² = 2

or, 2m²+3m - 2= 0

or, 2m² + (4 - 1)m -2 = 0

or, 2m² + 4m - m - 2 = 0

or, 2m(m + 2) - 1(m+2) = 0

or, (m + 2) (2m - 1) = 0

Either, Or,

m = -2 m = 1/2

Required angle is,

Recently we're working to degrade accounts with 0 contributions from creator to learner. If you're a learner and very keen to be a creator, you must keep posting interesting questions and contact to admins from the Facebook Group of Mattrab Community. For being an admin, you must be in grade 12, either completed or recently enrolled, your notes, and all your records and contributions will be verified for that

Aksionov used to drink a lot, was riotous, and was involved in illegal activities before his marriage

Program to input any number and display number of odd numbers in it;

#include<stdio.h>

#include<stdlib.h>

#include<conio.h>

#include<string.h>

int main() {

int i, number, num1, num2=0, num3, num4 =0, rem, rem1, rem2, rev = 0;

printf("Enter your number ==> ");

scanf("%d", &number);

num1 = number;

while(num1 != 0) {

rem = num1%10;

rem1 = rem%2;

if (rem1 != 0) {

num2 = num2*10 + rem;

}

num1 /= 10;

}

num3 = num2;

while (num2 != 0) {

...