Here, the given equation of parabola is y2= 8x.
The equation of tangent to the parabola y2=8x is,
y= mx + 2/m
This tangent passes through the point (-2, 3)
So, 3 = -2m + 2/m
or, 3m + 2m2 = 2
or, 2m2+3m - 2= 0
or, 2m2 + (4 - 1)m -2 = 0
or, 2m2 + 4m - m - 2 = 0
or, 2m(m + 2) - 1(m+2) = 0
or, (m + 2) (2m - 1) = 0
Either, Or,
m = -2 m = 1/2
Required angle is,
0 Thanks
2 Answers
4 Claps
0 Comments
14 Claps
0 Comments
1.ans: No the tension in the string of a simple pendulum is not constant throughout the motion
v is velocity of the bob and theta is the angle made by the string with vertical axis.as v and both are variable T is also variable.T is maximum at mean position as at mean position v is max and the angle is minimum.
2.ans: If the amplitude of the simple...
1 Thanks
2 Answers