A piece of cube of wood supporting a 200 g mass just floats in water. When the mass is removed, the cube rises by 2 cm. what is the size of cube?
LetMbe the mass of wooden cube andabe the side of the cube.
The body is in equilibrium in both cases. So lets equate the forces in both cases.
Case I:
0.2g+Mg=ρwV1g......(1)
Case II:
Mg=ρwV2g.......(2)
Here,V1=V2+a2.(0.02)V1V2=a2.(0.02)
Now, by subtracting(2)from(1), we get
0.2g+MgMg=ρw(V1V2)g
0.2g=ρwg(0.02.a2)
a2=0.20.02ρw=101000=0.01 m2a=0.1 ma=10 cm