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Solution:
The breaking stress = 7.982 10⁸ N/m² ;
the density of steel, ρ = 8.1 10³ kg/m³
Suppose A is the area of cross-section of the steel wire and L is the longest length of the steel wire.
We have,
 the weight of the wire = mg = (volume density)g
or F = LAρg 

Solution:
The length of a copper wire, LC = 1.5 m;
the length of a steel wire, LS = 1.5 m;
the diameter of the wires, d = 2 mm = 2 10^–3 m;
the composite length, L = 3 m;
the extended composite length, L' = 3.003 m;
the total extension, l = L' – L = 3.003 – 3 = 0.003 m;
the extension of the copper wire, l_C = ?;
the extension of the steel wire, l_S = ?

 l_C + l_S = 0.003 … (1)

For the copper wire, Young modulus,

Solution:
The extension, l = ?;
the force applied, F = 30 N;
the length of a copper wire, L = 2 m;
the diameter of the wire, d = 3 mm = 3 10^–3 m
The cross-section area of the wire,

Solution:
The side of a cube, L = 4 cm = 0.04 m;
the shear length, x = 0.012 cm = 1.2 10^–4 m

Solution:
The radius of a sphere, r = 10 cm = 0.10 m;
the increase in pressure, p = 5 10⁸ N/m² ;
the bulk modulus, B = 3.14 10¹¹ N/m² ;
the change in volume, V = ?