Weight of a body is less in the mines. Why?
The weight of a body is less in the mines because when we move deeper the earth gravity decreases but our mass is always constant.
If a body is taken to a pole from the equator, what happens to its mass and weight?
We all know that,
g = (G.M)/R2
g ∝ 1/R2
From this, we conclude g is inversely proportional to the square of the radius of any heavenly body. In the equator, the radius is longer than that in the pole. The longer the radius, the less g. So, there is a higher g at the pole than that in at the equator.
So, the weight of any body will increase, if it is taken from equator to pole becasue we have W = mg where mass remenins constant.