Calculate the free energy change and entropy change per mole when liquid water boils against 1 atmospheric pressure [ for water d H = 2.0723 kj/gm]
ΔHvap of water=2.072318=37.30KJmol1
ΔSvap=ΔHvapTb=37.30KJmol1373K=0.1kJmol1K1
ΔGvap=ΔH(kJmol1)T(K)ΔS(kJmol1)
=37.303730.1=0