Prove by the method of induction that xn-yn is divisible by x-y
Let P(n) be the statement: 
x n – yn is divisible by x – y. 
 For n = 1, x 1 – y1 = x – y is divisible by (x – y)
 Thus, P(1) is true.
 
Assume that P(k) is true, i.e., for kN x k – yk is divisible by (x – y)
Now, For P(k + 1) 
 Xk+1  – yk+1  = xk . x – yk y = xk.x – xk . y + xk .y – yk . y
 
(Adding and subtracting xk.y) 
= xk(x – y) + y (xk – yk )
As xk(x – y) is divisible by (x – y) and (xk – yk ) is divisible by 
 (x – y),therefore, xk+1 – yk+1 = xk(x...