Arinah Khatiwada

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Which principle goes against the concept of Bohr's fixed orbit? State the principle.

Heisenberg uncertainty principle goes against the concept of Bohr's atomic model.

It states that it is impossible to determine the exact position as well as momentum of a microscopic moving particle.

Write the electronic configuration of i. Copperii. Potassium

The electronic configuration of
i. CU₂₉= 1s², 2s² 2p⁶, 3s² 3p⁶, 4s¹ 3d¹⁰
ii. K₁₉= 1s², 2s² 2p⁶, 3s² 3p⁶, 4s¹

What is the conclusion made by de-brogile? Write its mathematical relationship.

The de-Brogile equation refers a moving particle's wavelength with its momentum. The Brogile wavelength is the wavelength, , associated with a moving particle and is relevant to its momentum, p, through the Planck constant, h. In other words, you can say that matter behaves like waves.

= h/p

How many number of oxygen molecules are required to produce 220mg of CO2 according to the reaction?C + O2 → CO2

The balanced chemical equation is given as

C + O₂ CO₂

Given mass of CO₂ = 220mg = 0.22g

44g of CO₂ is produced from 6.022 x 10²³ oxygen molecules.

0.22g of CO₂ can be produced from 3.011 x 10²¹ oxygen molecules.

How many grams of sulphur and oxygen are needed to produce 6.023 x 1024 molecules of SO2 according to the reaction?S + O2 → SO2

The balanced chemical equation is given as:

S + O₂ SO₂

According to the reaction

6.022 x 10²³ molecules of SO₂ are produced from 32g sulphur.

6.022 x 10²⁴ molecules of SO₂ are produced from = 320g sulphur

Similarly,

6.022 x 10²³ molecules of SO₂ are produced from 32g of oxygen

6.022 x 10²⁴ molecules of SO₂ can be produced from = 320g oxygen

Calculate mass in gram of a. two atom of carbonb. three molecules of hydrogen

Two atoms of Carbon:

1 mole of carbon = 12g
1 mole of carbon = 6.022 x 10²³ carbon atom

Thus,
6.022 x 10²³ carbon atom has mass 12g
2 carbon atom has mass = 3.98 x 10^-23 g carbon.

Three molecules of hydrogen:

1 mole of hydrogen molecule = 2g
1 mole of hydrogen molecule = 6.022 x 10²³hydrogen molecule

Thus,
6.022 x 10²³ hydrogen molecule has mass 2g hydrogen.

3 hydrogen molecules has mass = 9.96 x 10^-24g

How many number of moles of CO will be left when 2 x 1021 molecules are removed from 0.28g of CO?

Given,

The given weight of CO = 0.28 g
The molecular weight of CO = 28g

No. of moles of CO = 0.01 mole

We know that,

1 mole of CO contains 6.022 x 10²³ molecules
0.01 mole of CO contains 0.01 x 6.022 x 10²³ molecules = 6.022 x 10²¹ molecules

The number of molecules left is (6.022 x 10²¹ - 2 x 10²¹) = 4.022 x 10²¹ molecules

We know that,

6.022 x 10²³ molecules of CO = 1 mole of CO

4.012 x 10²¹ molecules of CO = 6.68 x 10^-3

Hence, no. of mole of CO left is 6.68 x 10^-3