2g of magnesium is burnt in a closed vessel containing 3g of oxygen. i. Which one is limiting reactant? ii. Calculate the mole of reactant left...
Solution:
The required balance chemical equation:
2Mg + O2---------------> 2MgO
i) For limiting reactant.
According to the balanced chemical equation.
48g Mg reacts with 32g of O2
1g Mg reacts with (32 48)g of O2
2g Mg reacts with 0.67 2g O2
But the mass of O2given is 3g. This means that Mg is finished first in the reaction. So, Mg is limiting reactant.
ii.
Given mass of O2= 3g
Consumed mass of O2= 1.33g
Therefore,
No. of O2left over =...