Find the derivative of (sinh(x/a) + cosh (x/a)) ^ nx.
=Arc tan sinhx
let y= arc tan sinhx
differentiating with respect to x,then
dy/dx=d(arc tan sinhx0/dx
dy/dx=d(arc tan sinhx)/d(sinhx) *d(sinhx0/dx
dy/dx=1/(1+sinhx)* coshx
dy/dx=coshx/cosh^2x=sechx
answer..