What is the pH of 10-9 M HCl?
Here , [H+] for acid is < 10 -7 { which is not possible }
so,
total [H+] = 10 -7 + 10 -9
= 1.01 x 10 -7
Thus, pH = - log [H+]
= 6.99
Calculate the pH value of 0.04 N HNO3 solution, assuming HNO3 to be completely ionized.
HNO3 ------------> H+ + NO3-
given,
concentration of acid = 0.04 N = 0.04 M
thus, [H+] = 0.04 M
pH = - log [ 0.04 ]
= - log [ 0.04 ]
= 1.39