What is the pH of 10-9 M HCl?
Here , [H+] for acid is < 10 -7 { which is not possible }
so,
total [H+] = 10 -7 + 10 -9
= 1.01 x 10 -7
Thus, pH = - log [H+]
= 6.99
Calculate the strength in g/liter of NaOH whose pH value is 11.
Given,
pH of NaOH is 11
i.e. - log [ H+ ] = 10-11
thus, [OH-] = 10 -14 / 10 -11
= 10 -3 mole/liter
molecular weight of NaOH is 40 g/mole
thus, in the strength is g/liter = 40 x 10 -3
= 0.04 g/liter