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Motion of electron in a uniform magnetic field

213

Hello there

Ani let’s say electron took time t to cover those distance
Hamilai formula thaha xa

               s = ut + ½ a t2

So, x direction ma

x = ux t + ½ a t2

x axis ma no influence of electrostatic force, so F = 0 => a = 0

               So, x = ux t

ð  t = x/ux  ……………………………..(i)

Aba y direction ma

               y = uy t + ½ a t2 ……………………… (ii)

aba y direction ma electrostatic force lagxa
which is F = E e

ð  ma = Ee

ð  a = Ee/m

In (ii),

               y = uy t = ½ Ee/m t2

Aba suru ma ta velocity in y direction 0 thiyo

So uy  = 0

ð  y = ½ Ee/m t2

Also, from (i),

ð  y = ½ Ee/m x2/ux2

Here,

Electric Field (E) is constant

Charge of electron (e) is constant

Mass of electron (m) is constant

Velocity in x direction (ux) is constant

That means, we can say

ð  y ∝ x2

This is in quadratic form
matlab parabola 🎈