The blocks A and B have equal masses. The surface of A is smooth but that of B has a friction coefficient of 0.1 with the floor. Block A is moving at a speed of 10 m/s towards B which is kept at re...
a) In a lab frame of reference,
Velocity of center of mass is given by,
v'=(mvOA+ mvOB)/2m

Now, in center of mass frame of reference,

Since, there will be perfectly elastic collision. After collision, they exchange their velocity.

In lab frame of reference,

Deceleration due to the friction =µg
From kinematics we have,
VF=VB-µgt
Since the final velocity of B is zero, we get t=10s.
Distance travelled d is given by,
d = VBt - (µgt2)/2
Inserting given values, the distance travelled by block is 50m.
b)...