1 Physics -- Mechanical Waves

In a stormy day a boy observes a lightening flash which is followed by a thunder 3 sec. later. How would you estimate the distance of the lightening strike from the boy? ( given, velocity of sound on that day= 332 m/s, velocity of light c= 3*10^8 m/s.

In a stormy day a boy observes a lightening flash which is followed by a thunder 3 sec. later. How would you estimate the distance of the lightening strike from the boy? ( given, velocity of sound on that day= 332 m/s, velocity of light c= 3*10^8 m/s.

Time taken (t) = 3 sec
Velocity of sound (v) = 332 m/s
Distance travelled (d) = ?

We know,

d = v x t = 332 x 3 = 996 m

Hence, the source of thunder is about 996 m far from the boy.

In this question, we have nothing to do with the velocity of light. The basic concept lies in the velocity of light is way greater than the velocity of sound. So, the light reaches the ground earlier than the sound reaches the ground.

Here, it says followed by. So, the time must have been calculated after the lightning was observed. Therefore, the actual distance between the origin of lightning and the observer is obtained by the velocity of sound.

Hence

distance (d) = velocity of sound * time

= 332 * 3

= 996 m

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