20 Physics -- Rate of Heat Flow

 Two bulbs of equal volume are joined by a narrow tube and are filled with a gas at STP. When one bulb is kept in melting ice and the other in boiling water, calculate the new pressure of the gas.

 Two bulbs of equal volume are joined by a narrow tube and are filled with a gas at STP. When one bulb is kept in melting ice and the other in boiling water, calculate the new pressure of the gas.

According to Charles' Law, the pressure of a gas is directly proportional to its temperature, provided the volume and the number of moles of the gas remain constant.

Assuming that the two bulbs have equal volumes and contain the same amount of gas, and that the tube connecting them is narrow enough so that the gas behaves as if it were in a single container, we can use Charles' Law to calculate the new pressure of the gas.

At STP (standard temperature and pressure), the temperature is 0 degrees Celsius and the pressure is 1 atm (atmosphere).

When one bulb is kept in melting ice, its temperature will be 0 degrees Celsius, and when the other bulb is kept in boiling water, its temperature will be 100 degrees Celsius. We can express these temperatures in Kelvin by adding 273.15:

The temperature of the bulb in melting ice is 273.15 K.

The temperature of the bulb in boiling water is 373.15 K.

Using Charles' Law, we can set up the following proportion:

Here, P1= 1atm

T1 = 273.15 K

T2 = 373.15 K

P2 = ?

Then, 

Therefore, the new pressure of the gas is 1.366 atm.

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