48 Science -- Force

A stone is thrown upwards with a velocity of 72 km/hr. If the air resistance is neglected, find the maximum height travelled by it.

A stone is thrown upwards with a velocity of 72 km/hr. If the air resistance is neglected, find the maximum height travelled by it.

Solution:

Initial velocity of stone (u) = 72 km/hr = 72 * 1000/3600 = 20 m/s

The stone is acted by constant downward acceleration equal to the acceleration due to gravity of earth, i.e, a = -g = - 10 m/s2

At maximum height, the velocity of the stone becomes 0 for a very short time so, final velocity of stone (v) = 0 m/s

To find: maximum height (H) = ?

Using equations of motion,

v2 = u2 + 2aH

or, 02 = (20)2 + 2(-10)H

or, 0 = 400 - 20H

or, 20H = 400

or, H = 400/20

So, H = 20 m

Hence, the maximum height travelled by the stone is 20 m.

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