Answer is B.

Solution:

The self-inductance is given as,

L = (µo) N² A / l

l = 50 cm = 0.5 m

r = 2cm = 0.02 m

A = pi * r^2 = pi * (0.02)^2

N = 500

Hence, L = (4 pi * 10^-7) * (500)^2 * (pi * (0.02)^2) / (0.5)

= 7.896 * 10^-4 Henry

The perpendicular component of the magnetic field due to the upper half of the coil is cancelled due to the field produced by the lower half of the coil as both are equal in magnitude and opposite in direction.

Hence, the perpendicular components of the field on the axis are not considered in the calculation of net magnetic field.

A moving coil galvanometer is based on the principle that a current-carrying coil or loop placed in a region of a magnetic field experiences a torque.

Current sensitivity of a galvanometer defines the deflection produced in the coil per unit current supplied to the galvanometer. A high current sensitivity implies a larger deflection for each unit rise in current.

In a galvanometer, the pole pieces of magnets are often cut into cylindrical form to enhance the uniformity and strength of the magnetic field within the coil.

Current carrying selonoid tends to contract because when current flows through a solenoid, the currents in the various turns of the solenoid are parallel and in the same direction. Since the currents flowing through parallel wires in the same direction lead to force of attraction between them, the turns of the solenoid will also attract each other and as a result the solenoid tends to contract.

In the presence of a magnetic field, a charged particle, such as an electron, experiences a force known as the Lorentz force. The Lorentz force is given by the equation:

F = q * (v x B)

where F is the force experienced by the particle, q is the charge of the particle, v is its velocity, and B is the magnetic field vector.

In this equation, the cross product (v x B) represents the direction of the force. The force is perpendicular to both the velocity vector (v) of the particle and the magnetic...

A charge particle carrying a charge q moves in an electric field 'E'. If its specific charge is 'S', then force is given as

F = qE

and acceleration, a= F/m = SE ( since, q/m= S given )

acceleration, a = SE

When a fast moving charge particle enter to a magnetic field as well as force is developed in the charge which is F = Bqv sinΘ, where B is magnetic field intensity, q is the charge, v is the velocity of charge particle and Θ be the angle between the velocity and magnetic fields. Due to this reason, the fast moving charge particle affect the magnet.

Yes, a charged particle moving through a magnetic field always experiences a force. This force, known as the Lorentz force, is perpendicular to the particle's velocity and the magnetic field direction. It causes the particle to move in a curved path. The magnitude of the force depends on the charge, velocity, and strength of the magnetic field.