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- by Shrajesh thapa 4 months ago

(a)__Variation of g due to the shape of the earth__

-Since earth is approximately an ellipsoid ( flattened at the poles and bulged at the equator), the equatorial radius is greater than polar radius by 21 km.

Mathematically,

*Fig. variation of g due to the shape of the earth*

Value of g on the surface of the earth is given by

Therefore , value of g is greater in pole than in the equator.

(b)__Variation of g due to Height(Altitude) __

-The value of acceleration due to gravity decreases with height.

[*Variation of force of gravity with the distance from the earth*]

-Let g and be the acceleration due to gravity on the surface of the earth and at height ‘h’ above the surface of the earth respectively .

*Fig. Acceleration due to gravity at a height 'h'*

Acceleration due to gravity on the surface of the earth is given by ,

where M is the mass of the earth and R is the radius of the earth,

Similarly, acceleration due to gravity at the height ‘h’ from the surface of the earth is given by,

Dividing equation (ii) by (i),

Thus value of acceleration due to gravity decreases with increase in the height above the surface of the earth.

__Variation of g due to the Depth __-The value of acceleration due to gravity decreases with depth.

[*When an object is at distance r from the center, only the mass inside a sphere of radius r exerts a net gravitational force on it*]

-If a body is taken to a depth ‘d’ below the earth’s surface , the body will be attracted only by the mass (M’) of the earth which is enclosed by a sphere of radius r=R-d .

*Fig. Acceleration due to gravity at a depth d *

Acceleration due to gravity at depth ‘d’ is given by the expression,

Thus ,the value of acceleration due to gravity decreases with increment in depth below the surface of the earth .

-When d=R we get g’=0..i.e acceleration due to gravity at the center of the earth is zero.

__Comparison of g inside, on and above the earth__

* fig. variation of g inside and outside the earth*

- The value of g linearly increases with the increase in distance from center of earth

- It attains maximum value at the surface.

- Above the surface of the earth , it decreases following inverse square law.

__Variation of g due to Rotation of Earth __-The acceleration due to gravity decreases due to the rotation of the earth.

-When the earth is not rotating the weight(W) of an object with mass ‘m’ at a point 'p' on the surface of the earth at latitude of 'φ' is ,

W=mg

*Fig. Variation of g due to the rotation of the earth *The resultant of the force of gravity and centrifugal force is given by ,

This is the required expression for the variation of acceleration due to gravity due to the rotation of the earth .This equation shows that due to rotation of the earth , the acceleration due to gravity decreases.

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