Problem involving three sets
SetProblem involving three setsQ. In a city, three daily newspapers A B and C are published. 42% read newspaper A, 51% read nespaper B, 68% read newspaper C, 30% read newspaper A and B, 28% read...
Set
Problems related to two sets
Q. In a survey of community, it was found that 70% liked curd, 60% liked milk, 20% didn't like both and 550 people liked both curd and milk. Then,
Solution:
Let U, C and M represents the set of total people in survey, people who like curd and milk respectively.
Given: n(C)=70% n(M)=60% n(C∪M)'=20% n(U)=100%
n(C∩M)=550
We know,
n(C∪M)= n(U) - n(C∪M)'
= 100% - 20%
= 80%
And, (C∩M) = n(C)+ n(M)- n(C∪M)
=70%+ 60%- 80%
= 50%
Let the total no. of people in the survey be x.
According to the question,
50% of x = 550
or, (50/100)*x = 550
or, 0.5 x = 550
or, x = 550/0.5
or, x = 1100
Now, n०(C)= n(C) -n(C∩M) [०=only]
=70%-50%
=20%
Then, 20%of 110=(20/100)*1100= 22
Venn-diagram: