A divalent metal oxide contains 60% of metal. What is atomic weight of metal?
wt of metal= 60 g
wt of oxygen= (100-60) g= 40 g
Eq. wt. of metal = wt. of metal/ wt of oxygen* 8
= 12
As metal is divalent, At. wt= Eq. wt* valency= 12*2 = 24
Carbon combines with hydrogen to form three binary compounds X, Y and Z. The percentage of hydrogen in X, Y and Z is 25%, 14.3% and 7.7% respectively, which law of chemical combination is illustrated by this data?
Solution:
Given,
In the compound X,
% of hydrogen = 25% & % of carbon = (100 – 25)% = 75% 25 parts by weight of hydrogen combine with 75 parts by weight of carbon.
1 part by weight of hydrogen combine with parts by weight of carbon
= 3 parts by weight of carbon
In the compound Y,
% of hydrogen = 14.3% & % of carbon = (100 – 14.3)% = 85.7% 14.3 parts by weight of hydrogen combine with 85.7 parts by weight of carbon
1 part by weight of hydrogen combine with parts by weight of carbon
=5.99 parts by weight of carbon
In the compound Z,
% of hydrogen = 7.7% & % of carbon = (100 – 7.7)% = 92.3% 7.7 parts by weight of hydrogen combine with 92.3 parts by weight of carbon
1 part by weight of hydrogen combine with parts by weight of carbon
= 11.98 parts by weight of carbon Hence the ratio of weight of carbon which combines with constant weight of hydrogen i.e. 1 part by weight of hydrogen is 3 : 5.99 : 11.98 =
= 1 : 1.99 : 3.99 i.e. 1 : 2 : 4 which is simple whole number ratio. Hence this data illustrate law of multiple proportions.