ABCD is a parallelogram. P is the point of intersection of the diagonals and if O is any point show that OA⃗+OB⃗+OC⃗+OD⃗=4OP⃗
ABCD is a parallelogram.
P is the point of intersection of the diagonals and if O is any point show that OA⃗+OB⃗+OC⃗+OD⃗=4OP⃗
Given, ABCD is a parallelogram
P is point of intersection of the diagonals
O is any point
Let OA,OB,OC,OD and OP be drawn.
Then we have,
Now,
(∵ For a parallelogram P bisects the two diagonal.)