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Hello Subash!
Here is the solution for the question you are asking for, I solved it in procedural way but if you are among the one who prefer OOP style then you can still ask it for me cause I have solved it from both methods but here I am just going to leave procedural one....
//author:Manish Acharya
import java.util.Scanner;
import java.util.*;
public class idgenerator {
public static void main(String[] args) {
String small_name="", long_name="", new_small_name="", new_long_name="";
char lr='a', rl='b';
int k=0, compare=0;
String id, reverse="";
Scanner userinput = new Scanner(System.in);
System.out.println("Enter the first name:");
String first_name = userinput.nextLine();
System.out.println("Enter the last name:");
String last_name = userinput.nextLine();
System.out.println("Enter the PIN:");
String pin = userinput.nextLine();
System.out.println("Enter any number N:");
System.out.println("Note: The given number should be less than or equal to PIN in length:");
int number = userinput.nextInt();
//checking part
if(number<=pin.length()) {
if(first_name.length() < last_name.length()) {
small_name = first_name;
long_name = last_name;
}
else if(first_name.length() > last_name.length()) {
long_name = first_name;
small_name = last_name;
}
else if(first_name.length() == last_name.length()) {
compare = first_name.compareTo(last_name);
if(compare<0) {
small_name = first_name;
long_name = last_name;
System.out.println("yes");
}
else if(compare>0){
long_name = first_name;
small_name = last_name;
}
else {
System.out.println("They are same!");
}
}
else {
System.out.println("Caught an unknown error!");
}
}
else {
System.out.println("Invalid number entered!");
}
//lowercase to uppercase and vice versa
for(int i=0; i<small_name.length(); i++) {
char a = small_name.charAt(i);
if(a >= 97 && a <= 123)
{
a = Character.toUpperCase(a);
}
else if(a >= 65 && a <= 96)
{
a = Character.toLowerCase(a);
}
new_small_name = new_small_name + a;
}
for(int i=0; i<long_name.length(); i++) {
char a = long_name.charAt(i);
if(a >= 97 && a <= 123)
{
a = Character.toUpperCase(a);
}
else if(a >= 65 && a <= 96)
{
a = Character.toLowerCase(a);
}
new_long_name = new_long_name + a;
}
//getting number from left to right and vice versa
for(int j=0; j<number; j++) {
lr = pin.charAt(j);
}
for(int j=pin.length()-1; j>=0; j--) {
reverse = reverse + pin.charAt(j);
}
for(int j=0; j<number; j++) {
rl = reverse.charAt(j);
}
//printing out id
System.out.println("Your ID is:" + new_small_name.charAt(new_small_name.length()-1) + new_long_name + lr + rl);
}
}
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First learn basic HTML, then CSS and responsive CSS for Static websites and thereafter JavaScript and PHP for dynamic pages. If you also want to learn jQuery for more better works learn it at the same time with JavaScript
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The terms “pass by value” and “pass by reference” are used to describe how variables are passed on. To make it short: pass by value means the actual value is passed on. Pass by reference means a number (called an address) is passed on which defines where the value is stored.