Bishesh Gautam asked a question

Here, the given equation of parabola is y2= 8x.

The equation of tangent to the parabola y2=8x is,

y= mx + 2/m

This tangent passes through the point (-2, 3)

So, 3 = -2m + 2/m

or, 3m + 2m2 = 2

or, 2m2+3m - 2= 0

or, 2m2 + (4 - 1)m -2 = 0

or, 2m2 + 4m - m - 2 = 0

or, 2m(m + 2) - 1(m+2) = 0

or, (m + 2) (2m - 1) = 0

Either, Or,

m = -2 m = 1/2

Required angle is,




0 Thanks
2 Answers
Close Open App